Posted by Daisy on .
An airplane flying at 550 miles per hour has a bearing of 53°. After flying for 2.5 hours, how far north and how far east will the plane have traveled from its point of departure?
I'm having a REALLY hard time with this one. I don't know what I'm doing wrong. Can someone walk me through this?

TRIG 
Reiny,
If you are using standard notation, then a bearing of 53° would be 53° clockwise from North
make a sketch.
Start the plane at the origin, then draw a line 53° form the yaxis (NOrth) and make it 2.5(550) or 1375 miles long. Complete the rightangled triangle, whose base angle will be 37°
distance north:
y/1375 = sin37
y = 827.5 miles
distance east:
x/1375 = cos 37
x = 1098.1 miles