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December 20, 2014

December 20, 2014

Posted by **Marissa** on Monday, October 15, 2012 at 11:37pm.

- Calculus -
**Steve**, Tuesday, October 16, 2012 at 10:19amwe know these limits exist as h->0:

(f(a+h)-f(a))/h

(g(a+h)-g(a))/h

sum of limits is thus

(f(a+h)-f(a) + g(a+h)-g(a))/h

= (f(a+h)+g(a+h) - (f(a)+g(a))/h

= ((f+g)(a+h) - (f+g)(a))/h

the limit is d(f+g)/dx at x=a

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