Hydrogen gas was collected over water in a eudiometer at 26 degrees celcius when the atmospheric pressure was 756 mm Hg. What was the pressure of the H2 gas?
the correct "hpelling" headass boi
Note the correct Hpelling of celsius.
Ptotal = pH2O + pH2
Ptotal = 756 mm Hg.
pH2O = vapor pressure of H2O at 26 C. Look up the vapor pressure of H2O at that T, then substitute and solve for pH2.
thank you so much for your help!
To find the pressure of the hydrogen gas, we need to correct for the partial pressure of water vapor. The total pressure in the eudiometer is the sum of the partial pressures of hydrogen gas and water vapor.
First, we need to determine the partial pressure of water vapor at 26 degrees Celsius. We can use the vapor pressure table or equation to find this value. Let's say the partial pressure of water vapor is x mm Hg.
Now, we can determine the pressure of the hydrogen gas by subtracting the partial pressure of water vapor from the total pressure.
Pressure of H2 gas = Total pressure - Partial pressure of water vapor
= 756 mm Hg - x mm Hg
To find the partial pressure of water vapor at 26 degrees Celsius, we can use the Antoine equation or the vapor pressure table for water at different temperatures. The Antoine equation is commonly used to estimate vapor pressure:
log(P) = A - (B / (T + C))
Where P is the vapor pressure in mm Hg, T is the temperature in degrees Celsius, and A, B, and C are coefficients specific to the substance. For water, the Antoine equation coefficients are A = 8.07131, B = 1730.63, and C = 233.426.
Now, let's substitute the values into the equation:
log(x) = 8.07131 - (1730.63 / (26 + 233.426))
We can solve the equation to find the value of log(x), then find x by taking the antilog:
x = 10^(log(x))
Once we have the value of x, we can substitute it back into the equation to find the pressure of the hydrogen gas:
Pressure of H2 gas = 756 mm Hg - x mm Hg
This will give us the pressure of the hydrogen gas collected over water at 26 degrees Celsius.