I need to find the critical value of what I have here so far, and I am stuck can someone please help?
Percent of children depressed: 4.3%
1250= n
4.3/100= s/1250
53.75= sample mean
n=sample size
After, mid 2010:
Percent of children depressed: 5%
100= n
5/100= s/100
5= sample mean
n= sample size
Null hypothesis: p= 0.043
Alternative hypothesis: p> 0.043
q= 1-p= 1- .05= .95
z= (.05-.043)/ sq rt(.043*.95/1250)
z= 1.224
If you are trying to compare your test statistic to a critical value from a z-table, then use the significance level to determine the cutoff point. For example, if the significance level is .05 for a one-tailed test (alternative hypothesis shows a specific direction), then check the z-table and you will find the critical value to be +1.645. If the z-value you calculated is +1.224, then the null will not be rejected and you cannot conclude a difference in the population.
I hope this helps and is what you were asking.