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algebra 1

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A passenger plane and a jet leave att the same time from the same airport,traveling in opposite directions. The jet travels at twice the speed of the passenger plane. they are 2400 mi apart in 4 hours. Find the speed of the passenger plane and jet.

  • algebra 1 - ,

    speed of passenger ---- x mph
    speed of jet -----------2x mph

    they each went for 4 hours, so
    distance covered by jet = 4(2x) = 8x
    distance covered by pass = 4x

    8x + 4x = 2400
    12x = 2400
    x = 200

    passenger plane went 200 mph, and the jet went 400 mph

    Just noticed that I answered the same question back in Nov of 2007
    http://www.jiskha.com/display.cgi?id=1194411287

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