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April 20, 2014

April 20, 2014

Posted by **Diego** on Monday, October 15, 2012 at 7:49pm.

1 with magnitude 44 N

inclined at 163

◦

and F~

2 with magnitude 72 N

inclined at 236

◦

, measured from the positive

x axis with counterclockwise positive.

What is the magnitude of the resultant vector F~

1 + F~

2 ? Draw the vectors to scale on a

graph to determine the answer.

1. 130 N

2. 98 N

3. 123 N

4. 95 N

5. 52 N

6. 72 N

What is the direction of this resultant vector (between the limits of −180◦

and +180◦

from the positive x-axis) ?

1. 103◦

2. 6◦

3. 23◦

4. 37◦

5. −38◦

6. −150◦

- Physics -
**Henry**, Tuesday, October 16, 2012 at 10:11pmR = 44N@163o + 72N@236o.

X =Hor.= 44*cos163 + 72*cos236=-82.3 N.

Y =Ver.= 44*sin163 + 72*sin236=-46.8 N.

1. R^2=X^2 + Y^2=(-82.3)^2 + (-46.8)^2 =8963.53.

R = 95 N. = Resultant force.

tanAr = Y/X = -46.8/-82.3 = 0.56865.

Ar = 29.62o = Reference angle.

A = 29.62 + 180 = 210o,CCW. = -150o,CW.

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