Chester builds and collects models of boats and planes. He has 22 models all together chester has 8 more planes than he has boats. How many of each kind of model does he have?

Let B = boats

B + B + 8 = 22

2B = 14

B = 7

15 PLANES 7 BOATS 15-7=8 15+7=22

To solve this problem, we can use a system of equations. Let's say C represents the number of models of boats Chester has and P represents the number of models of planes Chester has.

We know that he has a total of 22 models, so we can write the equation:
C + P = 22

We also know that Chester has 8 more planes than he has boats:
P = C + 8

To solve this system of equations, we can use substitution.

First, substitute P in the first equation with the value C + 8 from the second equation:
C + (C + 8) = 22

Combine like terms:
2C + 8 = 22

Next, solve for C by subtracting 8 from both sides of the equation:
2C = 22 - 8
2C = 14

Divide both sides of the equation by 2:
C = 14 / 2
C = 7

Now that we have the value of C, we can substitute it back into one of the original equations to find the value of P. Let's use the second equation:
P = C + 8
P = 7 + 8
P = 15

Therefore, Chester has 7 models of boats and 15 models of planes.