2C6H6(l) + 15O2(g) --> 12CO2(g)+ 6H2O(g) how to calculate the ratio?
Ratio of what? Ratio of mols of one to mols of another. The coefficients in the balanced equation does all of that for you.
In this equation, 2 mols C6H6 = 15 mol O2 = 12 mols CO2 = 6 mols H2O.
So you can convert from mols of one substance to mols of another easily. For example, suppose we want to know how many mols O2 it will take to completely react with 10 mols C6H6?
10 mols C6H6 x (15 mols O2/2 mols C6H6) = 10 x (15/2) = 75 mols O2 required.
If I've guessed wrong about what you want repost here and I can follow up.
look it up
To calculate the ratio of moles or molecules in a balanced chemical equation, you need to compare the coefficients of the reactants and products.
In the given balanced chemical equation:
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(g)
The coefficients in front of each compound or element represent the relative number of moles or molecules involved in the reaction.
To calculate the ratio between any two compounds or elements in the equation, you compare their coefficients by dividing them.
For example, to calculate the ratio between C6H6 and CO2, you divide their coefficients:
Coefficient of C6H6 / Coefficient of CO2 = 2 / 12
This simplifies to:
1 / 6
Therefore, the ratio between C6H6 and CO2 is 1:6. This means for every 1 mole of C6H6, 6 moles of CO2 are produced.
Similarly, you can calculate the ratio between other compounds or elements in the equation using the same method.