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December 20, 2014

December 20, 2014

Posted by **Bill** on Monday, October 15, 2012 at 12:26pm.

Is it -y/(x+2siny)

- Calculus -
**Steve**, Monday, October 15, 2012 at 2:47pmHmm. I get sin2y

y + xy' = 2siny*cosy y' = 0

y' = -y/(x + 2siny cosy)

= -y/(x + sin2y)

don't forget that chain rule. . .

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