Posted by Anonymous on Monday, October 15, 2012 at 11:51am.
f ' (x) = 3x^2
when the curve crossess the x-axis, y = 0
x^3 - 8 = -
x^3 = 8
x = 2 , so we have the point (2,0)
when x = 2, slope = 3(4) = 12
y - 0 = 12(x-2)
y = 12x - 24
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