Posted by C.S. on Monday, October 15, 2012 at 11:20am.
deriv.
y=x(sinx)(cosx)

Calc  bobpursley, Monday, October 15, 2012 at 11:22am
y=uvw
y'=vwu' + uvw'+uwv'
It is just algebra, and probably some trig identities.

Calc  Steve, Monday, October 15, 2012 at 11:25am
use the product rule.
hard way:
(1)[(sinx)(cosx)] + {x(cosx)](cosx) + [x(sinx)](sinx)
= sinx cosx + xcos^2 x  xsin^2 x
= 1/2 sin 2x + xcos 2x
easier way:
y = 1/2 x sin 2x
y' = 1/2 (sin 2x) + 1/2 x (2cos 2x)
= 1/2 sin 2x + x cos 2x
Answer This Question
Related Questions
 PreCalc  Trigonometric Identities Prove: (tanx + secx 1)/(tanx  secx + 1)= ...
 Trig........  I need to prove that the following is true. Thanks (cosx / 1sinx...
 ap calc bc  hi! ok, i know that deriv(cscx) = cscxcotx and that deriv(cos) = ...
 Trigonometry Check  Simplify #3: [cosxsin(90x)sinx]/[cosxcos(180x)tanx] = [...
 Trigonometry.  ( tanx/1cotx )+ (cotx/1tanx)= (1+secxcscx) Good one! Generally...
 Precalc  prove the identity: (cosx)(tanx + sinx cotx)=sinx+cos(squared)x i ...
 Math  Verify the identity . (cscXcotX)^2=1cosX/1+cosX _______ sorry i cant ...
 Math  Pre Clac  Prove that each of these equations is an identity. A) (1 + ...
 trigonometry  can i use factoring to simplify this trig identity? the problem ...
 Mathematics  Trigonometric Identities  Prove: (tanx)(sinx) / (tanx) + (sinx...
More Related Questions