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July 5, 2015

July 5, 2015

Posted by **Kristi** on Sunday, October 14, 2012 at 10:09pm.

g(x)={x+2, x less than or equal to -3

1/2x-2, x>-3

- Math -
**Reiny**, Sunday, October 14, 2012 at 10:20pmfor x < -3 , sketch the line y = x+2

put an "open" point at (-3,-1) , showing the point is excluded

for x≥-3, sketch y = (1/2)x - 2

draw a "closed' point at (-3, -5/2) , showing that point is included.

- Math -
**Kristi**, Sunday, October 14, 2012 at 10:31pmIt's still giving me the wrong answer. and how do I plot -5/2, when the graph shows no decimals?

- Math -
**Reiny**, Sunday, October 14, 2012 at 10:37pmIf you are doing this kind of math, I am surprised that you didn't know that

-5/2 = -2.5 or -2 1/2

What do you mean by "it's still giving me the wrong answer" , what is "it"

- Math -
**Kristi**, Sunday, October 14, 2012 at 10:46pmThe table plot on my homework is givving me the wrong answer.

- ok , correction - Math -
**Reiny**, Sunday, October 14, 2012 at 10:58pmI did not read your question carefully enough

change it to:

for x ≤ -3 , sketch the line y = x+2

put an "closed" point at (-3,-1) , showing the point is**included**

for x>-3, sketch y = (1/2)x - 2

draw a "open' point at (-3, -7/2) , showing that point is**excluded**.

notice the second point is (-3, -7/2) or (-3, =3.5)

try it now.

The only other thing that could be wrong is that your second equation is

y = 1/(2x) -2 , but I doubt it.