Posted by Jiim on Sunday, October 14, 2012 at 9:37pm.
A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 575 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope to the left and to the right of the mountain climber.

Physics  Elena, Monday, October 15, 2012 at 1:26pm
ΣFx=0 0= T1•sin αT2•sin β
0= T1•sin αT2•sin β
ΣFy=0
m•g=T1•cos α+T2•cos β
T2= T1•sin α/sin β
m•g=T1•cos α+ T1•sin α•cos β /sin β =
=T1•cos α+ T1•sin α• /tanβ
T1=mg/(sinα/tanβ +cosα)=...
T2 =... 
Physics  Anonymous, Monday, September 19, 2016 at 8:39pm
T1=970.08
T2=892.76