A car traveling in a straight line has a velocity of +3.3 m/s. After an acceleration of 0.71 m/s2, the car's velocity is +8.8 m/s. In what time interval did the acceleration occur?
your completely wrong
An increase in speed of 5.5 m/s, achieved at an acceleration rate of 0.71 m/s^2', requires
5.5/0.71 seconds
To find the time interval in which the acceleration occurred, we can use the equation:
\(V_f = V_i + a \cdot t\)
Where:
\(V_f\) is the final velocity (8.8 m/s)
\(V_i\) is the initial velocity (3.3 m/s)
\(a\) is the acceleration (0.71 m/s²)
\(t\) is the time interval we want to find
Rearranging the equation to solve for \(t\):
\(t = \frac{V_f - V_i}{a}\)
Substituting the given values:
\(t = \frac{8.8 - 3.3}{0.71}\)
Calculating:
\(t = \frac{5.5}{0.71}\)
\(t \approx 7.75\) (rounded to two decimal places)
Therefore, the time interval in which the acceleration occurred is approximately 7.75 seconds.