Posted by **Sam** on Sunday, October 14, 2012 at 3:14pm.

Using the approximation log10^2=0.301, find:

log10^8

- Logarithms -
**Steve**, Sunday, October 14, 2012 at 3:27pm
since 10^8 = 10^8,

log 10^8 = 8

giving the exponent makes finding the log easy, since a log is in fact an exponent

log 100 = 2

because 10^2 = 100

- Wrong, typo -
**Damon**, Sunday, October 14, 2012 at 3:29pm
log 10^2 = IS NOT .301

but

log base 10 of 2 = .301

usually written log10(2)

I bet you want log base 10 of 8

log10 (2^3) = 3 log10(2) = 3(.301) = .903

which i bet is what your are looking for

- Logarithms -
**Sam**, Sunday, October 14, 2012 at 3:36pm
Yes Damon that's what I meant. Thanks!

- Logarithms - my bad -
**Steve**, Sunday, October 14, 2012 at 3:37pm
My bad. I didn't read the entire problem. I might even have caught the strange notation. Go with Damon.

- Logarithms -
**Sam**, Sunday, October 14, 2012 at 3:39pm
It's fine. Thanks

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