Posted by **Aust** on Sunday, October 14, 2012 at 3:05pm.

Consider the reaction

PCl3(ℓ) → PCl3(g)

at 298 K. If ∆H◦

is 32.5 kJ/mol, ∆S

◦

is

93.3 J/K mol, and ∆G

◦

is 4.7 kJ/mol, what

would be the boiling point of PCl3 at one

atmosphere?

- Chemistry -
**DrBob222**, Sunday, October 14, 2012 at 8:51pm
dGo = dHo - TdSo

Substitute for dH and dS, set dGo = 0, and solve for T (in kelvin).

dGo = 0 because that is that point that the liquid phase/gas phase is in equilibrium and dGop = 0.

The number you obtain is based on dHo and dSo not changing very much from the value you get from the tables at 298 K.

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