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October 1, 2014

October 1, 2014

Posted by **Ryan** on Sunday, October 14, 2012 at 1:17pm.

Find the zeroes given one is x^2-x-4.

I dont know what to do now. i tried synthetic division. pls help : D

- Precalculus -
**Damon**, Sunday, October 14, 2012 at 4:31pmx^4-4x^3+3x^2+8x-16

--------------------

x^2 - x - 4

= x^2 - 3 x + 4 by long division

x = [3 +/- sqrt (9-16) ]/2

[3 +/- i sqrt (7)]/2

for the second pair of complex roots

for the original 2 roots

x = [ 1 +/- sqrt(1+16)]/2

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