Precalculus
posted by Ryan .
x^44x^3+3x^2+8x16
Find the zeroes given one is x^2x4.
I don't know what to do now. i tried synthetic division. pls help : D

x^44x^3+3x^2+8x16

x^2  x  4
= x^2  3 x + 4 by long division
x = [3 +/ sqrt (916) ]/2
[3 +/ i sqrt (7)]/2
for the second pair of complex roots
for the original 2 roots
x = [ 1 +/ sqrt(1+16)]/2