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Math

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x^4-4x^3+3x^2+8x-16

Find the zeroes given one is x^2-x-4.

I don't know what to do now. i tried synthetic division. pls help : D

  • Math - ,

    Synthetic division is usually only done with linear divisors, for quadratic divisors use long algebraic division. That gave me ....

    (x^4-4x^3+3x^2+8x-16)/(x^2 - x - 4)
    = x^2 - 3x + 4

    so solving x^2 - 3x + 4 = 0
    x = (3 ± √-7)/2
    = (3 ± i√7)/2

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