posted by Ryan on .
Find the zeroes given one is x^2-x-4.
I don't know what to do now. i tried synthetic division. pls help : D
Synthetic division is usually only done with linear divisors, for quadratic divisors use long algebraic division. That gave me ....
(x^4-4x^3+3x^2+8x-16)/(x^2 - x - 4)
= x^2 - 3x + 4
so solving x^2 - 3x + 4 = 0
x = (3 ± √-7)/2
= (3 ± i√7)/2