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August 31, 2014

August 31, 2014

Posted by **Ryan** on Sunday, October 14, 2012 at 1:16pm.

Find the zeroes given one is x^2-x-4.

I dont know what to do now. i tried synthetic division. pls help : D

- Math -
**Reiny**, Sunday, October 14, 2012 at 3:50pmSynthetic division is usually only done with linear divisors, for quadratic divisors use long algebraic division. That gave me ....

(x^4-4x^3+3x^2+8x-16)/(x^2 - x - 4)

= x^2 - 3x + 4

so solving x^2 - 3x + 4 = 0

x = (3 ± √-7)/2

= (3 ± i√7)/2

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