Post a New Question

Calculus

posted by on .

A particle moves along a horizontal line so that at any time t its position is given by x(t)=cost-t. Time is measured in seconds and x is measured in meters.
a.) Find the velocity as a function t. Use your answer to determine the velocity of the particle when t=pi/6 seconds. Indicate units of measure.
b.) Find the acceleration as a function of the time t. Use your answer to determine the velocity of the particle when t=pi/6 seconds. Indicate units of measure.
c.) What are the values of t,0≤t≤2pi, for which the particle is at rest?
d.) What are the values of t, 0≤t≤2pi, for which the particle moves to the right?
e.) At t=pi/6 seconds, is the particle speeding up or slowing down? Justify your answer.

  • Calculus - ,

    x = cos t - t

    dx/dt = v = -sin t - 1
    sin pi/6 = sin 30 = 1/2
    so
    v = -1.5

    a = dv/dt = -cos t
    I think you want the acceleration a = -sqrt3/2

    when is v = 0 ?
    when sin t = -1 which is t = 3 pi/2

    when is v >0? when sin t <-1 which is never

    when t = pi/6 , a is negative so v is getting less negative so slowing down

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question