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Posted by on Sunday, October 14, 2012 at 8:50am.

1.In one dimensional motion, instantaneous speed v satisfies
0 ≤ v < v0.
(a) The displacement in time T must always take non-negative
values.
(b) The displacement x in time T satisfies – vo T < x < vo T.
(c) The acceleration is always a non-negative number.
(d) The motion has no turning points (choose the correct option and also explain how to solve)

2.The displacement of a particle is given by x = (t – 2)2 where x is in
metres and t in seconds. The distance covered by the particle in
first 4 seconds is
(a) 4 m
(b) 8 m
(c) 12 m
(d) 16 m (choose the correct option and also please explain how to solve)

3.At a metro station, a girl walks up a stationary escalator in time t1.
If she remains stationary on the escalator, then the escalator takeher up in time t2. The time taken by her to walk up on the moving
escalator will be
(a) (t1 + t2)/2
(b) t1t2/(t2–t1)
(c) t1t2/(t2+t1)
(d) t1–t2 (choose the correct option and also explain how to solve)

  • physics - , Sunday, October 14, 2012 at 4:02pm

    1. Since 0 ≤ v < v0 , this is decelerated motion.
    (d) The motion has no turning points .

    2. x=(t-2)2=2t-4 = 2•4 – 4 =4m
    (a) 4 m

    3. v(girl)=s/t1
    v(esc)=s/t2
    t=s/(v1+v2) = t1•t2/(t1+t2)
    (c)

  • physics - , Thursday, December 10, 2015 at 12:13pm

    1.(B)
    2.(B)
    3.(C)

  • physics - , Tuesday, March 29, 2016 at 9:56am

    thanks good one just in time once again thank you for such ugly easy answer you slime

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