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October 24, 2014

October 24, 2014

Posted by **help me out it's urgent** on Sunday, October 14, 2012 at 8:50am.

0 ≤ v < v0.

(a) The displacement in time T must always take non-negative

values.

(b) The displacement x in time T satisfies – vo T < x < vo T.

(c) The acceleration is always a non-negative number.

(d) The motion has no turning points (choose the correct option and also explain how to solve)

2.The displacement of a particle is given by x = (t – 2)2 where x is in

metres and t in seconds. The distance covered by the particle in

first 4 seconds is

(a) 4 m

(b) 8 m

(c) 12 m

(d) 16 m (choose the correct option and also please explain how to solve)

3.At a metro station, a girl walks up a stationary escalator in time t1.

If she remains stationary on the escalator, then the escalator takeher up in time t2. The time taken by her to walk up on the moving

escalator will be

(a) (t1 + t2)/2

(b) t1t2/(t2–t1)

(c) t1t2/(t2+t1)

(d) t1–t2 (choose the correct option and also explain how to solve)

- physics -
**Elena**, Sunday, October 14, 2012 at 4:02pm1. Since 0 ≤ v < v0 , this is decelerated motion.

(d) The motion has no turning points .

2. x=(t-2)2=2t-4 = 2•4 – 4 =4m

(a) 4 m

3. v(girl)=s/t1

v(esc)=s/t2

t=s/(v1+v2) = t1•t2/(t1+t2)

(c)

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