Posted by **Johnny** on Sunday, October 14, 2012 at 12:50am.

I'm trying to find why the linear function f(-x)=x√x^2+2 is negative when it should be neither. why are √'s not negatives?!?!?! Is it because √x can't cross over the y axis because √x can't be negative? Then why is it that the x on the outside of the function is negative and the whole thing is counted as a neither?!

- college math -
**Reiny**, Sunday, October 14, 2012 at 1:08am
First of all your function is not a linear function, (it is not a straight line)

Secondly, is it the way you typed it or is it

f(-x) = x√(x^2 + 2)

by the way,

f(x) = -x√(x^2+2)

for negative x's the graph rises in quadrant II

for positive x's the graph drops in quadrant IV

it crosses the x-axis at (0,0)

Wolfram shows this:

http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29

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