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November 28, 2014

November 28, 2014

Posted by **Johnny** on Sunday, October 14, 2012 at 12:50am.

- college math -
**Reiny**, Sunday, October 14, 2012 at 1:08amFirst of all your function is not a linear function, (it is not a straight line)

Secondly, is it the way you typed it or is it

f(-x) = x√(x^2 + 2)

by the way,

f(x) = -x√(x^2+2)

for negative x's the graph rises in quadrant II

for positive x's the graph drops in quadrant IV

it crosses the x-axis at (0,0)

Wolfram shows this:

http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29

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