Post a New Question

college math

posted by on .

I'm trying to find why the linear function f(-x)=x√x^2+2 is negative when it should be neither. why are √'s not negatives?!?!?! Is it because √x can't cross over the y axis because √x can't be negative? Then why is it that the x on the outside of the function is negative and the whole thing is counted as a neither?!

  • college math - ,

    First of all your function is not a linear function, (it is not a straight line)

    Secondly, is it the way you typed it or is it
    f(-x) = x√(x^2 + 2)

    by the way,
    f(x) = -x√(x^2+2)

    for negative x's the graph rises in quadrant II
    for positive x's the graph drops in quadrant IV
    it crosses the x-axis at (0,0)

    Wolfram shows this:
    http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question