Posted by **Johnny** on Sunday, October 14, 2012 at 12:50am.

I'm trying to find why the linear function f(-x)=x√x^2+2 is negative when it should be neither. why are √'s not negatives?!?!?! Is it because √x can't cross over the y axis because √x can't be negative? Then why is it that the x on the outside of the function is negative and the whole thing is counted as a neither?!

- college math -
**Reiny**, Sunday, October 14, 2012 at 1:08am
First of all your function is not a linear function, (it is not a straight line)

Secondly, is it the way you typed it or is it

f(-x) = x√(x^2 + 2)

by the way,

f(x) = -x√(x^2+2)

for negative x's the graph rises in quadrant II

for positive x's the graph drops in quadrant IV

it crosses the x-axis at (0,0)

Wolfram shows this:

http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29

## Answer This Question

## Related Questions

- Math - Find an equation of the line that bisects the obtuse angles formed by the...
- 8th grade algebra - Can you check my answers? 1. 3√20/√4 = 3√(...
- Algebra - How would i complete these problems? 1. (√6mn)^5 2. ^3√16x...
- maths - I will be thankfull to you if you help me to solve the below problem: 6...
- Algebra Work Check - 1. 5√6 * 1/6√216 5/6 * √1296 5/6 * √...
- Algebra 2 Answer Check - Simplify by rationalizing each denominator. 1. 2/√...
- algebra 1 - alright i have a few questions if its ok..? Simplify: 1. -2√(...
- Algebra 2 - Can someone help me with this radical expression please? The problem...
- Math - I need someone to check my homework answers. I don't really know this ...
- Math - Determine the exact value of cos 465 degrees a) √3 + √2/2 b...

More Related Questions