Math
posted by Anonymous on .
if n=45, calculate the number of cosets of An in Sn .

Your question makes no sense to me.

I'm not really sure about this, but I'll give it a go. By the way, what do you mean by cosets?
n=45
Solving for the number of (costs?) of An in Sn.
A45= S45
This is the most I can simplify it down to. If you post the full question from wherever you're getting it from, I may just be able to help. 
Answer is 2..
From Lagrange's Theorem, we know that the number of cosets in An in Sn is [Sn:An] = Sn/An = 2
Note An = n!/2 = Sn/2