Posted by Anonymous on Saturday, October 13, 2012 at 11:51pm.
Your question makes no sense to me.
I'm not really sure about this, but I'll give it a go. By the way, what do you mean by cosets?
n=45
Solving for the number of (costs?) of An in Sn.
A45= S45
This is the most I can simplify it down to. If you post the full question from wherever you're getting it from, I may just be able to help.
Answer is 2..
From Lagrange's Theorem, we know that the number of cosets in An in Sn is [Sn:An] = |Sn|/|An| = 2
Note An = n!/2 = |Sn|/2
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