Monday
March 27, 2017

Post a New Question

Posted by on .

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 11 from the takeoff point.
If the kangaroo leaves the ground at a 18 angle, what is its takeoff speed ?
What is its horizontal speed?

  • Physics - ,

    Takeoff Speed= Range=(initial velocity^2 * Sin (2 theta))/g

    11m = (V0^2*sin(36))/(9.8)

    V0= sqrt((11*9.8)/(sin36))

    V0=13.54

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question