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March 31, 2015

March 31, 2015

Posted by **Anonymous** on Saturday, October 13, 2012 at 9:05pm.

- physical -
**Henry**, Sunday, October 14, 2012 at 9:04pmd = 21km@255o + 30km@90o + 8km@0o.

X = hor. = 21*cos255 + 8 = 2.56 km.

Y = Ver. = 21*sin255 + 30*sin90=9.72 km.

a. d^2=X^2 + Y^2=(2.56)^2 + (9.72)^2=101

d = 10.1 km.

tanA = Y/X = 9.72/2.56 = 3.79688

A = 75.2o,CCW = 75.2o North of East = The Direction.

- physical -
**Anonymous**, Saturday, May 24, 2014 at 4:25am34

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