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October 30, 2014

October 30, 2014

Posted by **jack** on Saturday, October 13, 2012 at 5:57pm.

a. How far up the plane does it go?

b. How much time does it take to get there?

I was stuck after Fg(cos(theta+90)= Ma_x

gcos(90+theta)/M = a_x

can someone please help me

- newton's law -
**Damon**, Saturday, October 13, 2012 at 8:01pmkinetic energy at bottom = (1/2) M Vo^2

= potential energy at to when it stops

= m g h = M g (x sin theta)

so

(1/2) M Vo^2 = M g x sin thets

x = Vo^2/(2 g sin theta)

average speed = Vo/2

time = distance/average speed

= Vo^2/(2 g sin theta)] / [ Vo/2)]

= Vo/(g sin theta)

- newton's law -
**jack**, Sunday, October 14, 2012 at 6:47pmthanks but my instrutor dont want me to use energy to solve the problem since we havnt learn it yet, can you do it using newton's law?

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