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Posted by **Sonia** on Saturday, October 13, 2012 at 5:51pm.

Mass of filter paper/Lg.watch glass: 12.9912 g

Mass of filter paper/Lg.watch glass + X: 23.5899 g

Mass of filter paper/Sm.watch glass: 9.4332 g

Mass of filter paper/Sm.watch glass + Y: 12.1622 g

Calculate the following: 1. Mass of sample

2. Mass of X recovered

3. Mass of Y recovered

4. % X in the sample

5. % Y in the sample

6. Assuming the actual composition is 69.00% X and 31.00% Y, calculate the % error for each component. Indicate if the %Error represents a HIGH or LOW error relative to the accepted values.

- Science- Chemistry -
**Sonia**, Sunday, October 14, 2012 at 1:42amIs this right?

1. Mass of Sample:

= (mass of total)- (mass of empty tube)

= 25.4886 g - 10.2586 g

= 15.2300 g

2. Mass of X recovered:

= (mass of filter paper/large watch glass + X) - (mass of filter paper/lg. watch glass)

= 23.5899 g - 12.9912 g

= 10.5987 g

3. Mass of Y recovered:

= (mass of filter paper/small watch glass + Y) - (mass of filter paper/sm. watch glass)

= 12.1622 g - 9.4332 g

= 2.7290 g

4. % of X in sample:

= [(mass of X) / (mass of total)] * 100%

= (10.5987 g / 25.4886 g) * 100%

= 41.6%

5. % of Y in sample:

= [(mass of Y) / (mass of total)] * 100%

= (2.7290 g / 25.4886 g) * 100%

= 10.7%

6. Percent Error:

= [(|accepted value - determined value|) / (accepted value)] * 100%

For X:

= [(|.6900 - .416|) / (.6900)] * 100%

= 39.7%

For Y:

= [(|.3100 - .107|) / (.3100)] * 100%

= 65.4%

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