How do you solve this equation;

There are 128 7th graders at Mark's school, if there are 16 more girls than boys, how many 7th grade boys are there?

first you subtract 16 from the number of all students , then divide that number by two and you will get your answer .

128=x+16

128= number of total students.
X= the number of boys
so, 16+X because there are 16 more girls than boys...
so subract 16 from 128 which equals 112
so the number of boys is 112 and the number of girls is 112+16

Subtract 16 from the number of all students. 128 - 16 = 112. Divide 112 by 2 = 56. There are 56 BOYS and 56 + 16 = 72 GIRLS

Let boys=x and girls=x+16:-

boys + girls =218
x + (x+16 =218
2x + 16 =218
x = (218-16)/2
= 101
Hence boys =101 and girls =101+16

Hope this helps

In a survey, three out of seven people named blue as their favorite color. One out of six named red. If 1,092 people were included in the survey, how many named neither blue nor red as their favorite color (can any one help me

A. 650 people
B. 468 people
C. 442 people
D. 806 people

48

To solve this equation, let's first assign variables to the unknown quantities. Let's say the number of boys in 7th grade is represented by 'x'.

According to the problem, we know that there are 16 more girls than boys. So, the number of girls would be represented by 'x + 16'.

Since we also know that there are 128 7th graders in total, we can write the equation:

x + (x + 16) = 128

Now, let's solve the equation step by step.

Combining like terms, we get:

2x + 16 = 128

Next, let's isolate 'x' by subtracting 16 from both sides of the equation:

2x = 128 - 16
2x = 112

Finally, divide both sides of the equation by 2 to solve for 'x':

x = 112/2
x = 56

Therefore, there are 56 7th grade boys at Mark's school.