If the new line is parallel to 3x-y = -3 it must differ only in the constant.
So the new equation is
3x - y = c
but (0,0) lies on it, so
3(0) - 0 = c
c = 0
new equation :
3x - y = 0
y = 3x
Pre-cal - 10.2 can someone show me this graph(x+2)^2/4+(y+2)^2/15=1
Math applied/pre-cal - (-8/5)^7/4*(-8/5)^1/4=64/25 Not sure how get this answer...
physics - A 50 gram ice cube is cooled to -10oC in the freezer. How many ...
Science - A 50 gram ice cube is cooled to -10oC in the freezer. How many ...
pre cal - can someone please show me how to verify this identity? (sec x/csc x ...
Pre-Cal(Please help) - Use synthetic division to show that x is a solution of ...
Pre-cal/Trig - (tan/(1+sec)) + ((1+sec)/tan) = 2csc (Show all work please.)
pre-cal - find the intercepts. y=2x-2 show work
pre-cal - show solution solve. 2sin^(2)x=2+cosx
pre cal - does anyone take pre-cal online ?