Tuesday
March 28, 2017

Post a New Question

Posted by on .

Bob, who has a mass of 60 , can throw a 800 rock with a speed of 26 . The distance through which his hand moves as he accelerates the rock forward from rest until he releases it is 1.0 .

a) What constant force must Bob exert on the rock to throw it with this speed?

b)If Bob is standing on frictionless ice, what is his recoil speed after releasing the rock?

  • physics 100 - ,

    You need to provide dimensions with your numbers.

  • physics 100 - ,

    m1=60 kg, m2=0.8 kg, v=26m/s, s=1 m
    (a). a=v²/2s =26²/2•1=338 m/s²
    F=m1•a=60•338=20280 N (inhumanly large force... I believe that velocity has to be 2.6 m/s .... check your given data)
    (b)The law of conservation of linear momentum
    0= m1•v1-m2•v2
    v1= m2•v2/m1= 0.8•26/60=0.347 m/s

  • physics 100 - ,

    b. F = m*a = 0.8 * 338 = 270.4 N.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question