Monday
July 28, 2014

Homework Help: chemistry

Posted by ice cream on Friday, October 12, 2012 at 5:42pm.

For the diprotic weak acid H2A Ka1=2.1x10^-5 and Ka2=5.5x10^-7. What is the pH of a 0.0800M solution of H2A? What are the equilibrium concentrations of H2A and A^2- in this solution?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - For the diprotic weak acid H2A, Ka1 = 2.2 10-5 M and Ka2 = 7.8 ...
Chemistry - Given a diprotic acid, H2A, with two ionization constants of Ka1 = 3...
Chemistry - Given a diprotic acid, H2A, with two ionization constants of Ka1=3....
Chemistry - Consider a 0.10 M solution of a weak polyprotic acid (H2A) with the ...
chemsitry - Consider the diprotic acid H2A with K1 1*10^-3 and K2= 1*10^-9 . ...

Search
Members