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posted by LeAnne on Friday, October 12, 2012 at 5:09pm.
You wish to heat 30 kg of water from 60°C to 80°C. How many kcal of heat are necessary to do this? To how many kJ does this correspond?
1 kJ = 0.24 kcal c=4186 J/kg•K Q=cmΔT
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