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January 26, 2015

January 26, 2015

Posted by **nicky** on Friday, October 12, 2012 at 2:50pm.

- phy -
**bobpursley**, Friday, October 12, 2012 at 3:06pmin the vertical:

hf=hi+vi*t-4.9t^2

0=45+20*sin30*t-4.9t^2

put that in standard form for a quadratic

at^2+bt+c=0

use the quadratic equation

t=(-b+-sqrt(b^2-4ac))/2a

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