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March 29, 2017

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A 100 kg sample of a metal is cooled from 100°C to 20°C by removing 20 kcal of heat. Calculate the specific heat capacity of the metal.

  • Physical Science - ,

    20kcal=100kg*c*80 C

    c=20k/(100k*8O)=.2/80=.02/8
    = .0025 cal/g-C

  • Physical Science - ,

    20 kcal =83736 J
    Q=cmΔT

    c=Q/mΔT

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