Posted by karla on Friday, October 12, 2012 at 1:57pm.
........HClO ==> H^+ + OCl^-
I.....1.0E-4.....0........0
C........-x.......x.......x.
E......1E-4-x.....x.......x
Ka = (H^+)(OCl^-)/(HClO)
Substitute and solve for x = (H^+) = (OCl^-). (HClO) = 1.00E-4-x
You can get OH from
(H^+)(OH^-) = Kw
Thank You!!!
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