posted by Cicily on .
Question as follows:
75.0g tartaric acid in 1 Liter is what molarity(moles/liter) mw=150.087 g/mol
25 ml tartaric solution is titrated with 31 ml ammonium.
What is the equation rearanged for normality of ammonium: starting with N1V1=N2V2
Final Answer N2=
THANKS! I can't wrap my head around this!
M = mols/L and mols = g/molar mass.
Therefore, mols H2T(tartaric acid) = 75.0/150.087 = ?
and M = mols/L.
Nomality of H2T = 2*M
Then 25*N H2T = 31*N NH3. Solve for N NH3.
By the way I assume this is ammonia, the ammonium ion doesn't exist by itself.
Thank you DrBob222!