A 2.7 kg bucket of water is raised upwards by a rope. If the bucket has an acceleration of 3.4 m/s/s, find the force exerted by the rope on the bucket.
Wow! Four test (homework?) questions in under a minute. I hope you're not expecting answers anytime soon!
Try using the famous Newton's-second-law equation
F = M a
where M is the mass and a is the acceleration.
The product (F) will be in Newtons.
To find the force exerted by the rope on the bucket, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the mass of the bucket is given as 2.7 kg and the acceleration is given as 3.4 m/s^2. So, we can calculate the force exerted by the rope using the formula:
Force = mass × acceleration
Substituting the given values, we have:
Force = 2.7 kg × 3.4 m/s^2
Now we can multiply these values:
Force = 9.18 N
Therefore, the force exerted by the rope on the bucket is 9.18 Newtons.