Posted by JJ on .
A toy cannon fires a .11 kg shell with initial velocity vi=10m/s in the direction 52 degrees above the horizontal. The shell's trajectory curves downward because of gravity, so that time t=.61 s the shell is below the straight line by some vertical distance deltaH. find the distance "deltaH" in the absence of air resistance. the acceleration of gravity is 9.8 m/s^2. answers in units of m
What straight line are you measuring from?
y = y0 + 10*sin52*t -(g/2)*t^2
"DeltaH" = y0 - y
(assuming it is measured positive downwards)
Plug in for t and g and compute deltaH