Thursday

July 31, 2014

July 31, 2014

Posted by **peter** on Friday, October 12, 2012 at 7:19am.

- physics -
**bobpursley**, Friday, October 12, 2012 at 9:07amInteresting question.

the vertical height from the edge of the brick to the center is 18 inches. The horizontal distance from the edge of the brick to the center of gravity requires some calculation.

draw the figure. from the brick edge to the center is 20 inches. sketch a horizontal line frm the edge of the brick to the vertical downward radius. The You now have a triangle, 20 hypotenuse, 18 on the downward leg, and the horizontal leg will be d=sqrt(20^2-18^2)=sqrt(400-324)=sqrt 76 check that.

Now moments around the edge sum to zero.

F*18-weight*sqrt76=0

forceat center=72lbs*sqrt76/18

at the top, the process is similar.

Force*38-72sqrt76=0 solve for Force

**Related Questions**

physics - a roller whose diameter is 20 in weight 72 lbs. what horizontal force ...

physics - a roller whose diamater is 1.0m.weight 360N.what horizontal force is ...

Physics - A man using a 70 kg garden roller on a level surface exerts a force 20...

physics - a 4kg roller is attached to a spring of force constant 100N/m. it ...

physics - A lawn roller is rolled across a lawn by a force of 109 N along the ...

physics - A lawn roller is rolled across a lawn by a force of 109 N along the ...

physics - A lawn roller is rolled across a lawn by a force of 109 N along the ...

physics - Part of a roller-coaster ride involves coasting down an incline and ...

Physics- Elena please help! - Part of a roller-coaster ride involves coasting ...

physics - Consider a roller coaster as it travels near the bottom of its track ...