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December 19, 2014

December 19, 2014

Posted by **vikash** on Friday, October 12, 2012 at 6:52am.

- maths -
**Reiny**, Friday, October 12, 2012 at 9:06amI will assume you meant

r^3 = 3r cosŲ

Use: r^2 = x^2 + y^2 and x/r = cosŲ

so if rcosŲ = x

then 3rcosŲ = 3x

and r^3 = r^2 r

= (x^2 + y^2)(x^2+y^2^(1/2)

= (x^2 + y^2)^(3/2)

r^3 + 3rcosŲ ---> (x^2 + y^2)^(3/2) = 3x

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