Post a New Question

Physics

posted by on .

Help
a constant force equal to (5i+2j)N moves a particle through a displacement S=(2i+3j). Calculate the workdone by the force. At what angle to the horizontal was the force applied?

  • Physics - ,

    The work done is the dot product of force and displacement vectors, which is
    5*2 + 3*2 = 16 Joules

    If the j component is up and the i component is horizontal, the force angle from the horizontal is arctan(2/5) = 21.8 degrees.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question