Posted by Fiyin on .
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a constant force equal to (5i+2j)N moves a particle through a displacement S=(2i+3j). Calculate the workdone by the force. At what angle to the horizontal was the force applied?

Physics 
drwls,
The work done is the dot product of force and displacement vectors, which is
5*2 + 3*2 = 16 Joules
If the j component is up and the i component is horizontal, the force angle from the horizontal is arctan(2/5) = 21.8 degrees.