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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Friday, October 12, 2012 at 12:28am.

y = 3/√ x at the point where x = a > 0

- Math -
**Reiny**, Friday, October 12, 2012 at 8:55amy = 2x^(-1/2)

dy/dx = -x^(-3/2)

= -1/(√x)^3

so for x = a , a>0

dy/dx = -1/(√a)^3

- Math -
**Steve**, Friday, October 12, 2012 at 10:09amgood math, bad reading. :-(

- Math -
**Reiny**, Friday, October 12, 2012 at 12:01pmOh well, 2 or 3 , close enough.

blame it on "oldsheimers"

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