Children in a tree house lift a small dog in a basket 4.90m up to their house. If it takes 201J of work to do this, what is the combined mass of the dog and basket?

W=Fd

F=ma=mg

now solve for W

d=x=distance

W=ΔPE=mgh

m=W/gh

To solve this problem, we need to use the concept of work and potential energy.

Work is defined as the force applied over a distance. In this case, the work done to lift the dog and basket is given as 201J.

The work done to lift an object is equal to the change in potential energy. The potential energy of an object at a certain height is given by the formula P.E. = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and h is the height.

In this problem, the work done to lift the object is 201J, and the height is 4.90m. Therefore, we can write the equation:

201J = (m)(9.8 m/s^2)(4.90m)

Simplifying the equation:

201J = 48.02m

To isolate the mass (m), divide both sides of the equation by 48.02:

m = 201J / 48.02 ≈ 4.18 kg

Therefore, the combined mass of the dog and the basket is approximately 4.18 kg.

201/(9.82)(4.90)

4.18