Math
posted by Kevin .
(x3) is a factor of x^3+ax^2+bx3 but when divided by x+2 the remainder is 15
Solve for A and B
I know that A is 1 and B is 11, but I don't understand how to solve it

the easiest way is synthetic division. ivide f(x) by x3 to see that the remainder is
9a+3b+24
divide by x+2 and the remainder is
4a  2b  11
so, now you have two equations to solve
3a+b+8 = 0
4a  2b  11 = 15
Looks like the solution above is correct