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A swimmer can swim in still water at a speed
of 9.31 m/s. He intends to swim directly
across a river that has a downstream current
of 4.35 m/s.
a) How many degrees from straight across
the river should he head? Let upstream be a
positive angle.
Answer in units of degrees
b) What is the magnitude of the swimmer’s
velocity relative to the bank?
Answer in units of m/s

  • Physics - ,

    (a)tanα =u/v=4.35/9.31=0.467.
    α=arctan 0.467=25.04°
    (b) v(rel) =sqrt(v²-u²)=sqrt(9.31²-4.35²)=8.23 m/s

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