Thursday

April 17, 2014

April 17, 2014

Posted by **george** on Thursday, October 11, 2012 at 8:27pm.

After the blocks are released from rest, find the speed of each block after moving 4.00cm .

- physics -
**Elena**, Friday, October 12, 2012 at 3:22pmm2•a=m2•g-T

m1•g=T-F(fr)

a• (m1+m2) = m2•g-F(fr)=m2•g-μ•m1•g

a=g• (m2-μ•m1)/(m1+m2)

v=sqrt(2•a•s)

- physics -
**Elena**, Friday, October 12, 2012 at 3:23pmm2•a=m2•g-T

m1•g=T-F(fr)

a• (m1+m2) = m2•g-F(fr)=m2•g-μ•m1•g

a=g• (m2-μ•m1)/(m1+m2)

v=sqrt(2•a•s)

**Related Questions**

physics - A block with mass = 5.0 rests on a frictionless table and is attached ...

physics - A block with mass = 5.0 rests on a frictionless table and is attached ...

Physics - A block of mass m = 2.00 kg rests on the left edge of a block of mass ...

physics - A block with mass = 5.0 rests on a frictionless table and is attached ...

physics - A block with mass = 5.0 rests on a frictionless table and is attached ...

physics - a bullet of mass 0.04kg moving with a speed of 90m/s enter a heavy ...

physics - a bullet of mass 0.04kg moving with a speed of 90m/s enter a heavy ...

physics - A Block has a mass of 50.0 kilograms. the coefficient of static ...

Physics - Block A has a mass of 2.60 kg and rests on a smooth (frictionless) ...

Physics - A small block of mass m rests on the sloping side of a triangular ...