Homework Help: physic

Posted by derek on Thursday, October 11, 2012 at 8:15pm.

A charge of -2.73 μC is fixed in place. From a horizontal distance of 0.0465 m, a particle of mass 9.50 x 10-3 kg and charge -9.56 μC is fired with an initial speed of 97.2 m/s directly toward the fixed charge. What is the distance of closest approach?

physic - Elena, Friday, October 12, 2012 at 3:32pm
KE=PE
mv²/2=k•q1•q2/r

r=2•k•q1•q2/ mv² =
=2•9•10⁹•2.73•10⁻⁶•9.56•10⁻⁶/9.5•10⁻³•97.2²=
=5.23•10⁻³ m

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