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posted by Stacy on Thursday, October 11, 2012 at 5:04pm.
How would we make 500mL of a 1.5 percent w/v solution of KC1 in water?
1.5% w/v means 1.5 g HCl in 100 mL soln. You want 500 mL; therefore you will need 1.5 x (500/100) = g KCl in 500 mL soln.
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