Post a New Question


posted by .

How would we make 500mL of a 1.5 percent w/v solution of KC1 in water?

  • Chem -

    1.5% w/v means 1.5 g HCl in 100 mL soln. You want 500 mL; therefore you will need 1.5 x (500/100) = g KCl in 500 mL soln.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question