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Posted by on Thursday, October 11, 2012 at 11:35am.

A factory worker pushes a 30.7 crate a distance of 4.0 along a level floor at constant velocity by pushing downward at an angle of 31 below the horizontal. The coefficient of kinetic friction between the crate and floor is 0.26.

What magnitude of force must the worker apply to move the crate at constant velocity?

  • PHYSICS - , Thursday, October 11, 2012 at 11:58am

    downward? that means he is increasing friction.

    Friction force=mu(mg+Force*Sin31)

    horizontal force=force*cos31

    set them equal, solve for force.

  • PHYSICS - , Tuesday, November 6, 2012 at 6:01pm

    jhh

  • PHYSICS - , Sunday, March 3, 2013 at 10:03pm

    how is p u s s y a bad word?

  • PHYSICS - , Tuesday, April 2, 2013 at 3:52pm

    bob is correct, except that you have to subtract the Force*sin(31). It's a poorly worded problem, to say the least.

  • PHYSICS - , Tuesday, March 18, 2014 at 4:43pm

    Bajs i skärten

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