Posted by **Candice** on Thursday, October 11, 2012 at 9:38am.

A box contains 20 balls, of which 5 are red, 5 are blue, 5 are white and 5 are green. Suppose a sample of 5 balls are chosen without replacement.

a) find the probability that the sample contains balls of all the same colour

(answer is 4/ 20C5, but why isnt it 5/20C5??)

b) find the probability that the sample contains three balls of one colour and two balls of another colour.

The teacher wrote

5C3 x 5C2 x 4P2

---------------

20C5

Could you please explain why this is?

Thanks!!

- maths -
**Snehal**, Thursday, October 11, 2012 at 10:16am
a) the ans. is 4/20C5 because there are 4 types of balls and 5 is the magnitude of a specific colour.

b)5C3 gives value of 3 balls of 1 colour;

5C2= value of 2 balls of another colour;

4P2= probality of 2 colours from 4 colours ;

20C5=combination of total balls of different colour.

therefore:-5C3*5C2*4P2

-------------

20C5

- maths -
**ujjval**, Thursday, October 11, 2012 at 10:24am
Dinga chika

- maths -
**Reiny**, Thursday, October 11, 2012 at 10:38am
could be all red, all blue , all white or all green

prob(all red) = (5/20)(4/19)(3/18)(2/17)(1/16) = /15504

the same calculation for the others

so the prob(all same colour) = 4(1/15504) = 1/3876

which is the same as 4/C(20,5)

Why isn't it 5/C(20,5) ??

Why would it? There are only 4 colours

3 colours of one kind, 2 of the others :

RRRBB RRRWW RRRGG

BBBRR ...

..

WWWRR ................

There would be 12 of those

let's look at one such case

RRRBB

prob = C(5,3) x C(5,2)/C(20,5) = 10/15504

but there are 12 cases with the same colour triple, and another colour double

so prob = 12 x C(5,3) x C(5,2)/C(20,5)

= 1200/15504

= 25/323

which is the same as your teacher's answer

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