Posted by Herosugar on .
College Physics Center of Mass?
The objects in the figure below are constructed of uniform wire bent into the shapes shown (Figure 1) . Each peice has a length of 0.15 .
There are two objects that we need to figure out the x and ycoordinates of the center of mass of the object . Assume the origin to be at the bottom left point.
Help please
1. the first object is like a l_l the wires are connected in this exact shape.
2. is the shape of L
3. is an equilateral triangle.
Remember each side is 0.15m .. help me please

College physics  Center of mass 
drwls,
1. On axis of symmetry midway between vertical wires and 0.05 m above bottom wire.
2. Along a 45 degree from the corner of the L. 0.0375 m to the right of and 0.0375 m above the corner.
3. At the center of the triangle. (The center of symnmetry where the angle bisectors intersect.) 
College physics  Center of mass 
Herosugar,
Yes but how do we go about this.
Let me show you what I did for l_l 
College physics  Center of mass 
Elena,
r(C) = Σ{r(i) •m(i)}/Σm(i)
Assume the origin to be at the bottom left point and the mass of each part is ’m’
1. X(C) ={ 0+(L/2)+L}m/3m = L/2
Y(C) = { (L/2) +0+(L/2)}m/3m = L/3
C= (L/2; L/3) = (0.075;0.05).
2. X(C) ={ 0+(L/2)}m/2m = L/4
Y(C) = { (L/2) +0}m/2m = L/4
C= (L/4; L/4) = (0.0375;0.0375).
3. X(C) ={ L/2•cos60°)+(L/2)+(L L/2•cos60°)}m/3m = L/2
Y(C) = { (L/2•sin60°) +0+(L/2•sin60°))}m/3m = 0.29L
C= (L/2; L/3) = (0.075;0.0435).